Hi there!
As a trilingual teacher, I frequently encounter a Japanese mother who is positive about raising her children bilingually. No complaints, you know. That’s great. Then can she really make their kids into bilingual speakers in Japan? My answer is “No.”
I’ve seen many Japanese kids and business persons who study English conversation just in Japan; however, their mindsets are not going global due to their high-context language endorsing tacit understanding and non-verbal communications.
My kids stayed long in Latin America. They have felt non-Japanese lifestyles in their bones, encountering insecurity in daily life, such as mugging on the streets, burglary, a bandit in ranches and residential areas, and whatnot. There were countless other examples, you know.
Believe it or not, my kids have guts and remain placid even in shooting in the neighborhood.
Becoming a bilingual speaker or business person is not a stretch but a cinch. However, the bottom line is whether they can grow up into a cosmopolitan who can respond to any contingencies. Nothing ventured, nothing gained. Both children and business people need to have hands-on experiences to acquire wisdom; to get the knowledge is not enough to survive on the global scene.
Being positive about raising children bilingually is food for thought, but be seriously and fully prepared to nurture a true cosmopolitan.
Today, given the above positive thinking, let me challenge a word problem finding positive integers.
Find the smallest value of a positive integer \(n\) such that \(\sqrt{\frac{108}{n}}\) is an integer.
Here is my answer to the problem.
Firstly, factorize the numerator in the square root into prime factors.
Secondly, if the prime factors have the same numbers, remove them as two pieces in a set.
Finally, the remains become the answer on the condition that those numbers are to be multiplied if they exist in a plural number.
\(108 = 2・2・3・3・3・1\)
If the prime factors have the same numbers, remove them as two pieces in a set, so
\(108 = \require{cancel}\bcancel{2}・\bcancel{2}・\bcancel{3}・\bcancel{3}・3・1\), thus only the prime factors \(3\) and \(1\) remain.
The correct answer is \(3・1 = 3\).
Be a positive cosmopolitan business person!
Stay tuned, and expect to see my next post.
Keep well.
Frank Yoshida
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【グローバルビジネスで役立つ数学】でもっと学習する b＾＾)
【参考図書】『もう一度高校数学』（著者：高橋一雄氏）株式会社日本実業出版社
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